Explanation on a proof of the mean-value property for the heat equation.

Let $U\subset\mathbb^n$ be an open set, $\Phi$ the fundamental solution of heat equation, $T>0$, $r>0$, $x\in\mathbb^n$ and $t\in\mathbb$. Defines $U_T=U\times(0,T]$ and $$E(x,t;r)=\<(y,s)\in\mathbb^;\:s\leq t,\;\Phi(x-y,t-s)\geq r^\>.$$ I would like some explanations about the proof of the following

Theorem (mean-value property for the heat equation): Let $u\in C^2_1(U_T)$ solve the heat equation. Then $$u(x,t)=\frac\iint_u(y,s)\frac<|x-y|^2>\,dy\,ds.\tag$$

Obviously, from $(1)$ follows $$u(0,0)=\frac<1>\iint_u(y,s)\frac<|y|^2>\,dy\,ds.\tag$$ However, the proofs that I saw (for exemple this one, page 4) proves $(2)$. So, my question is: how to prove that $(2)\Rightarrow(1)$? Thanks.

asked Oct 6, 2013 at 19:04 19.3k 8 8 gold badges 68 68 silver badges 132 132 bronze badges

$\begingroup$ Is there something preventing you from following the exact same proof as in your reference for arbitrary $x,t$? $\endgroup$

Commented Oct 6, 2013 at 19:10

1 Answer 1

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The reason (2) implies (1) is that the heat equation is invariant under translation in space-time. That is, if $u$ satisfies the PDE, then for any fixed $(x_0,t_0)$ the translated function $\tilde u(x,t)=u(x+x_0,t+t_0)$ also satisfies the PDE. This is easy to check by taking the derivatives of $\tilde u$ with the chain rule.

So, to prove (1) at the point $(x_0,t_0)$, one can apply (2) to $\tilde u$ defined above, obtaining $$\tilde u(0,0)=\frac\iint_\tilde u(y,s)\frac<|y|^2>\,dy\,ds \tag $$ Then return to $u$: $$\tilde u(x_0,t_0)=\frac\iint_ u(y+x_0,s+t_0)\frac<|y|^2>\,dy\,ds $$ and finally change the variables in the integral: $\tilde y=y+x_0$, $\tilde s=s+t_0$.

You may wonder why do all of this, instead of simply proving (1) directly (which is not very different from proving (2)). But with enough experience, people notice the translation-invariance in their problems right away, and simply say: we can take $(x,t)=(0,0)$ without losing generality, by translating the function. (Or something of the kind. Or say nothing at all, considering it obvious.)

TeXnical note: the proper way to number displayed formulas here is with \tag , as I did above.